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jancraats:hoofdstuk_18 [2012/05/15 19:21] – created randyjancraats:hoofdstuk_18 [2022/09/01 11:44] (current) – external edit 127.0.0.1
Line 3: Line 3:
 $$ $$
 \begin{split} \begin{split}
-2^{1 + x} \cdot 3^x = \\+&2^{1 + x} &\cdot 3^x  \\ 
 +& 2^1 \cdot 2^x &\cdot 3^x  \\ 
 += & 2^1 &\cdot 6^x  \\ 
 += & 2 &\cdot 6^x 
 +\end{split}  
 +$$ 
 + 
 +====== 18.1e ======
  
 +$$
 +\begin{split}
 +& 4^{2x} : 2^x \\
 += &(4^2)^x : 2^x \\
 += &16^x : 2^x \\
 += & \left( \frac{16}{2} \right) ^x \\
 += & 8^x 
 \end{split}  \end{split} 
 +$$
jancraats/hoofdstuk_18.1337109712.txt.gz · Last modified: 2022/09/01 11:36 (external edit)