a

$$ \begin{cases} 2x + 3y = 4 \\ 3x - 2y = 6 \end{cases} $$

$$ \frac { \begin{cases} 6x + 9y = 12\ (3x) \\ 6x - 4y = 12\ (2x) \end{cases} } { 0 + (9y - -4y) = 0 \\ 13y = 0 \\ y = \frac{0}{13} \\ y = 0 } - $$

$$ \begin{split} 2x + 3 \cdot 0 & = 4 \\ x & = \frac{4}{2} \\ x & = 2 \end{split} $$