jancraats:hoofdstuk_18
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18.1d
$$ \begin{split} 2^{1 + x} &\cdot 3^x = \\ 2^1 \cdot 2^x &\cdot 3^x = \\ 2^1 &\cdot 6^x = \\ 2 &\cdot 6^x \end{split} $$
jancraats/hoofdstuk_18.1337109870.txt.gz · Last modified: 2022/09/01 11:36 (external edit)