jancraats:hoofdstuk_18
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18.1d
$$ \begin{split} 2^{1 + x} &\cdot 3^x \\ = 2^1 \cdot 2^x &\cdot 3^x \\ = 2^1 &\cdot 6^x \\ = 2 &\cdot 6^x \end{split} $$
18.1e
$$ \begin{split} 4^{2x} &: 2^x = \\ (4^2)^x &: 2^x = \\ 16^x &: 2^x = \\ & \left( \frac{16}{2} \right) ^x = \\ & 8^x \end{split} $$
jancraats/hoofdstuk_18.1337111772.txt.gz · Last modified: 2022/09/01 11:36 (external edit)