jancraats:hoofdstuk_18
This is an old revision of the document!
18.1d
$$ \begin{split} &2^{1 + x} &\cdot 3^x \\ = & 2^1 \cdot 2^x &\cdot 3^x \\ = & 2^1 &\cdot 6^x \\ = & 2 &\cdot 6^x \end{split} $$
18.1e
$$ \begin{split} & 4^{2x} &: 2^x \\ = &(4^2)^x &: 2^x \\ = &16^x &: 2^x \\ = & \left( \frac{16}{2} \right) ^x \\ = & 8^x \end{split} $$
jancraats/hoofdstuk_18.1337111879.txt.gz · Last modified: 2022/09/01 11:36 (external edit)