wortel

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1.2b

$ ( - \frac{1}{3} \cdot \sqrt{6} \cdot i ) ^ 2 \newline - \frac{1^2}{3^2} \cdot 6 \cdot i^2 \newline \frac{1}{9} \cdot 6 \cdot -1 \newline \frac{6}{9} \cdot -1 \newline \frac{2}{3} \cdot -1 \newline -\frac{2}{3} $