<?xml version="1.0" encoding="UTF-8"?>
<!-- generator="FeedCreator 1.8" -->
<?xml-stylesheet href="https://wortel.tty32.org/lib/exe/css.php?s=feed" type="text/css"?>
<rdf:RDF
    xmlns="http://purl.org/rss/1.0/"
    xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
    xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
    xmlns:dc="http://purl.org/dc/elements/1.1/">
    <channel rdf:about="https://wortel.tty32.org/feed.php">
        <title>wortel inleiding_dsp</title>
        <description></description>
        <link>https://wortel.tty32.org/</link>
        <image rdf:resource="https://wortel.tty32.org/lib/tpl/dokuwiki/images/favicon.ico" />
       <dc:date>2026-05-14T11:10:47+00:00</dc:date>
        <items>
            <rdf:Seq>
                <rdf:li rdf:resource="https://wortel.tty32.org/doku.php?id=inleiding_dsp:hoofdstuk_4&amp;rev=1662032649&amp;do=diff"/>
            </rdf:Seq>
        </items>
    </channel>
    <image rdf:about="https://wortel.tty32.org/lib/tpl/dokuwiki/images/favicon.ico">
        <title>wortel</title>
        <link>https://wortel.tty32.org/</link>
        <url>https://wortel.tty32.org/lib/tpl/dokuwiki/images/favicon.ico</url>
    </image>
    <item rdf:about="https://wortel.tty32.org/doku.php?id=inleiding_dsp:hoofdstuk_4&amp;rev=1662032649&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2022-09-01T13:44:09+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>inleiding_dsp:hoofdstuk_4</title>
        <link>https://wortel.tty32.org/doku.php?id=inleiding_dsp:hoofdstuk_4&amp;rev=1662032649&amp;do=diff</link>
        <description>4.9-4.12 (blz 117)

1)
$$
H(z) = \frac{1}{ z(z-1)(2z-1) } = \frac{ Y(z) }{ X(z) }
$$

2)
$$
Y(z)\{{z(z-1)(2z-1)}\} = X(z)
$$

3)
$$
z (z-1)(2z-1)
$$

We groepen dan eerst het merkwaardige product en noemen dit X
$$
z \underbrace{(z-1)(2z-1)}_\text{X}
$$

$$
X = 2z^2 - z - 2z + 1
$$

Nu kunnen we de z vermenigvuldigen met de uitgewerkte X term
$$
\eqalign{
z \cdot X &amp;= z ( 2z^2 - z - 2z + 1 ) \\
          &amp;= 2z^3 - \underbrace{z^2 - 2z^2} + z \\
          &amp;= 2z^3 - 3z^2 + z
}
$$

4)

Nu kunnen we…</description>
    </item>
</rdf:RDF>
